Wednesday 27 November 2013

Question on Series

What will be the maximum sum of 44, 42, 40, ... ?

(A) 502
(B) 504
(C) 506
(D) 500

Answer: C

Explanation :
44 + 42 + 40 + 38 + ..... + 4 + 2 + 0 + (-2) + (-4) + ....

This series is maximum when the series reaches 2.

So, the sum of
= 44 + 42 + 40 + 38 + ..... + 4 + 2
= 2 (22 + 21 + 20 + .... + 1)
= 2 (22 * 23) /2
= 506

Topics to revise :
Arithmetic Expressions

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