A tourist covers half of his journey by train at 60 km/h, half of the remainder by bus at 30 km/h and the rest by cycle at 10 km/h. The average of the tourist in km/h during his entire journey is
(A) 36
(B) 30
(C) 24
(D) 18
Answer: (C)
Explanation :
Lets assume the distance = X
Time it took for the tourist to cover first part of the journey = (X/2)/60 = X/120
Time it took for the tourist to cover second part of the journey = (X/4)/30 = X/120
Time it took for the tourist to cover third part of the journey = (X/4)/10 = X/40
Total time it took for the journey = X/120 + X/120 + X/40 = 5X/120
Average speed of the journey = Distance/ Time = X / (5X/120) = 120/5 = 24 Kmph
(A) 36
(B) 30
(C) 24
(D) 18
Answer: (C)
Explanation :
Lets assume the distance = X
Time it took for the tourist to cover first part of the journey = (X/2)/60 = X/120
Time it took for the tourist to cover second part of the journey = (X/4)/30 = X/120
Time it took for the tourist to cover third part of the journey = (X/4)/10 = X/40
Total time it took for the journey = X/120 + X/120 + X/40 = 5X/120
Average speed of the journey = Distance/ Time = X / (5X/120) = 120/5 = 24 Kmph
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